a regular octagon with sides of length 7 and an apothem of length 10.49 has an area of _____ square units
Accepted Solution
A:
Answer: 293.72Step-by-step explanation: Since the apothem is length 10.49, and half the side-length is 3.5, the octagon can be divided into 16 right triangles, each with base b = 3.5 and height h = 10.49. The area of each triangle is (1/2)bh. Since there are 16 of them, the total area A of the octagon is: A = (16)(1/2)bh = 8bh = (8)(3.5)(10.49) = 293.72